Wednesday, July 07, 2010

Thoughts on why you can't logically disprove god to a theist.

Consider this:

given some real, non-zero value, a

        a = b
a*b = b2
a*b-a2 = b2-a2
a*(b-a) = (b-a)*(b+a)
a = b+a

This is obviously wrong. You don't even need to understand the algebra to see that it's wrong. If a is not zero, and a equals b, then a cannot equal a+b. The argument is nonsense. Identity is not a conclusion. It is an axiom. It is foundational to mathematics.

As far as theists are concerned, the same thing applies to their god. If your logic leads to the conclusion that their god doesn't exist, then, to theists, there is obviously something wrong with your logic; even if they can't say what that is, exactly. For them, their god is an axiom, foundational to reality. Only when a theist is able to reject that premise as false can they be reasoned with.

That is why I stick to "Evidence or STFU" when someone challenges my atheism.

Later,

4 people have spouted off:

tom said...

Error: division by zero.

tom said...

1 = 1
-1 = -1 (and -1 = 1/-1 = -1/1)
(-1)/1 = 1/(-1)
take square root of both sides, then:
i/1 = 1/i
cross multiply (1x1) = (ixi):
1 = -1

PS: italicized i's = neato HTML

John said...
I know there's a division by zero error there. My point was that you don't even need to be able to see that to know that the algebra is wrong.
8/21/10, 10:54 AM
John said...
also, in the proof you give, the error is that you haven't taken into account that numbers have 2 square roots.

√(1) = 1 or -1
√(-1) = i or -i

PS: italicized i's may be neato HTML, but can be confusing, what with all the i's involved. Especially when typing in a hurry.
8/21/10, 11:39 AM